Select the incorrect match.

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(D) is the incorrect match. $H_2O$ has a higher boiling point than $HF$. Although $F$ is more electronegative than $O$,each $H_2O$ molecule can form f

Vedclass · Accepted Answer

$H_2O < HF \Rightarrow 	ext{Boiling point}$

Vedclass · Answer

(D) is the incorrect match. $H_2O$ has a higher boiling point than $HF$. Although $F$ is more electronegative than $O$,each $H_2O$ molecule can form four hydrogen bonds on average,while each $HF$ molecule forms only two. Therefore,the correct order of boiling point is $H_2O > HF$. Other options are correct: $o	ext{-nitrophenol}$ is more volatile (higher vapour pressure) than $p	ext{-nitrophenol}$ due to intramolecular hydrogen bonding. Glycerol $(HO-CH_2-CH(OH)-CH_2-OH)$ is more viscous than glycol $(HO-CH_2-CH_2-OH)$ due to more $-OH$ groups and stronger intermolecular hydrogen bonding.

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