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(D) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^{2-}$ ($18$ elect

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(D) According to Molecular Orbital Theory $(MOT)$,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For $O_2^{2-}$ ($18$ electrons): Bond order $= 1$,unpaired electrons $= 0$.For $O_2^{-}$ ($17$ electrons): Bond order $= 1.5$,unpaired electrons $= 1$.For $O_2$ ($16$ electrons): Bond order $= 2$,unpaired electrons $= 2$.For $O_2^{+}$ ($15$ electrons): Bond order $= 2.5$,unpaired electrons $= 1$.$1$. Bond length is inversely proportional to bond order: $O_2^{2-} (1) > O_2^{-} (1.5) > O_2 (2) > O_2^{+} (2.5)$. This is correct.$2$. Bond strength is directly proportional to bond order: $O_2^{+} (2.5) > O_2 (2) > O_2^{-} (1.5) > O_2^{2-} (1)$. This is correct.$3$. Number of unpaired electrons: $O_2 (2) > O_2^{+} (1) = O_2^{-} (1) > O_2^{2-} (0)$. This is correct.Since all statements are correct,the answer is $D$.

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