Select the best method for the preparation of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The target compounds are a pair of enantiomers of $trans-2-methylcyclohexanol$.Step $1$: Reaction of cyclohexene with $MCPBA$ (meta-chloroperoxybe

Vedclass · Accepted Answer

reaction of cyclohexene with $MCPBA$,followed by $CH_3MgBr$

Vedclass · Answer

(D) The target compounds are a pair of enantiomers of $trans-2-methylcyclohexanol$.Step $1$: Reaction of cyclohexene with $MCPBA$ (meta-chloroperoxybenzoic acid) yields cyclohexene oxide (epoxide).Step $2$: The nucleophilic ring-opening of the epoxide with a Grignard reagent like $CH_3MgBr$ occurs via an $S_N2$ mechanism,leading to the trans-addition of the methyl group and the hydroxyl group.Therefore,the reaction of cyclohexene with $MCPBA$ followed by $CH_3MgBr$ is the correct method.

Select the best method for the preparation of the following compounds:
(Image shows a mixture of trans$-2-$methylcyclohexanol enantiomers)
($MCPBA$ = meta-chloroperoxybenzoic acid)

Similar Questions

$3 \ mol$ of ethanol reacts with $1 \ mol$ of phosphorus tribromide to give $3 \ mol$ of bromoethane and $1 \ mol$ of $X$. What is $X$?

Which of the following compounds will yield $Propanone$ upon dehydrogenation?

The effective factor in the preparation of alkene from alcohol using $Al_2O_3$ is ................ .

$ROH + HX \to RX + H_2O$
In the above reaction,the reactivity order of hydrogen halides is

Explain the mechanism of dehydration of alcohols with a suitable example.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Select the best method for the preparation of the following compounds:(Image shows a mixture of trans$-2-$methylcyclohexanol enantiomers)($MCPBA$ = meta-chloroperoxybenzoic acid)