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(B) reaction is favoured in the forward direction if a stronger acid reacts with a stronger base to form a weaker acid and a weaker base. In option $B

Vedclass · Accepted Answer

Anilinium ion + $o$-toluidine $\rightleftharpoons$ Aniline + $o$-toluidinium ion

Vedclass · Answer

(B) reaction is favoured in the forward direction if a stronger acid reacts with a stronger base to form a weaker acid and a weaker base. In option $B$,the reaction is: $C_6H_5NH_3^+ + o-CH_3C_6H_4NH_2 \rightleftharpoons C_6H_5NH_2 + o-CH_3C_6H_4NH_3^+$. Here,$o$-toluidine $(o-CH_3C_6H_4NH_2)$ is a stronger base than aniline $(C_6H_5NH_2)$ due to the electron-donating $+I$ effect of the $-CH_3$ group. Therefore,$o$-toluidine will accept the proton more readily than aniline,shifting the equilibrium to the right (forward direction).

Select the reaction which will be favoured in the forward direction.

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