According to the Bronsted-Lowry concept,the c | vedclass

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(C) The relative strength of bases is inversely proportional to the strength of their conjugate acids.$1$. The conjugate acid of $OH^{-}$ is $H_2O$ $(

Vedclass · Accepted Answer

$OH^{-} > CH_3COO^{-} > Cl^{-}$

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(C) The relative strength of bases is inversely proportional to the strength of their conjugate acids.$1$. The conjugate acid of $OH^{-}$ is $H_2O$ $(K_a \approx 10^{-14})$.$2$. The conjugate acid of $CH_3COO^{-}$ is $CH_3COOH$ $(K_a \approx 1.8 	imes 10^{-5})$.$3$. The conjugate acid of $Cl^{-}$ is $HCl$ (a strong acid,$K_a$ is very high).Since the strength of conjugate acids follows the order $HCl > CH_3COOH > H_2O$,the strength of the corresponding conjugate bases follows the reverse order: $OH^{-} > CH_3COO^{-} > Cl^{-}$.

According to the Bronsted-Lowry concept,the correct order of relative strength of bases follows the order:

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