See the electrical circuit shown in the adjoi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Applying Kirchhoff's voltage law to the loop $ABFE$ in the clockwise direction:Starting from point $A$ and moving towards $B$,the potential drop a

Vedclass · Accepted Answer

$E_1 - (i_1 + i_2)R - i_1r_1 = 0$

Vedclass · Answer

(D) Applying Kirchhoff's voltage law to the loop $ABFE$ in the clockwise direction:Starting from point $A$ and moving towards $B$,the potential drop across resistor $R$ is $-(i_1 + i_2)R$.Moving from $F$ to $E$ through the branch containing $E_1$ and $r_1$,we encounter the negative terminal of the battery first,so we add $E_1$,and the potential drop across $r_1$ is $-i_1r_1$.Equating the sum of potential changes to zero,we get:$-(i_1 + i_2)R - i_1r_1 + E_1 = 0$Rearranging the terms,we get:$E_1 - (i_1 + i_2)R - i_1r_1 = 0$

See the electrical circuit shown in the adjoining figure. Which of the following equations is a correct equation for it?

Similar Questions

In the given part of a circuit,the potential at point $B$ is zero. Then the potentials at $A$ and $C$ respectively are

The current from the cell for the given circuit is ................ $A$.

The charge accumulated on the capacitor connected in the following circuit is . . . . . . $\mu C$ (Given $C=150\ \mu F$)

If the resistances are chosen for the circuit shown in the figure in such a way that no current flows through the battery with emf $E_1 = 2 \ V$,the voltage $V_2$ across $R_2$ and the current $I_3$ flowing through $R_3$ are respectively,

What is the value of the current flowing through the galvanometer in the balanced condition of a Wheatstone bridge?

Vedclass Test Series

Exam Paper Generator

Online Exam Module