The same mass of $CH_4$ and $H_2$ is taken in a container. The partial pressure caused by $H_2$ is:

  • A
    $8/9$
  • B
    $1/9$
  • C
    $1/2$
  • D
    $1$

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For the complete combustion of $15 \ mL$ of a gaseous hydrocarbon at $300 \ K$ and $1 \ atm$ pressure,$375 \ mL$ of air containing $20\% \ O_2$ by volume is required. After combustion,the gases occupy $330 \ mL$. Assuming that the water formed is in liquid state and the volumes are measured at the same temperature and pressure,find the formula of the hydrocarbon.

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At $300 \ K$ and $1 \ \text{atm}$ pressure,$10 \ mL$ of a hydrocarbon required $55 \ mL$ of $O_2$ for complete combustion,and $40 \ mL$ of $CO_2$ is formed. The formula of the hydrocarbon is

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