Resultant intensity at the centre of the scre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For coherent sources,the resultant intensity at the center (where path difference is zero) is given by $I_{max} = (A_1 + A_2)^2$. Assuming equal a

Vedclass · Accepted Answer

$\frac{I_0}{2}$

Vedclass · Answer

(D) For coherent sources,the resultant intensity at the center (where path difference is zero) is given by $I_{max} = (A_1 + A_2)^2$. Assuming equal amplitudes $A_1 = A_2 = A$,we have $I_0 = (A + A)^2 = 4A^2$.Since intensity $I$ of a single source is $A^2$,we have $I_0 = 4I$,which implies $I = \frac{I_0}{4}$.For incoherent sources,the interference term averages to zero over time. Therefore,the resultant intensity is simply the sum of the individual intensities: $I_R = I_1 + I_2$.Substituting $I_1 = I_2 = I = \frac{I_0}{4}$,we get $I_R = \frac{I_0}{4} + \frac{I_0}{4} = \frac{2I_0}{4} = \frac{I_0}{2}$.

Resultant intensity at the centre of the screen due to two coherent sources is $I_0$. If the sources are incoherent,then the intensity at the same point will be

Similar Questions

In the interference of two coherent sources of different intensities,the ratio of maximum and minimum intensity is $\frac{I_{\max}}{I_{\min}} = \frac{144}{81}$. What is the ratio of their amplitudes?

The ratio of maximum and minimum intensities in an interference pattern is $36: 1$. The ratio of the amplitude of the two interfering waves will be

The phenomenon of interference is observed in .........

Two independent monochromatic light sources produce waves given by $y_1 = 2 \sin \omega t$ and $y_2 = 3 \cos \omega t$. Which of the following statements is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module