Resolving power of a telescope can be increas | vedclass

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Question

(D) The resolving power of a telescope is defined as the inverse of the minimum angular separation between two objects that can be just distinguished

Vedclass · Accepted Answer

the diameter of the objective.

Vedclass · Answer

(D) The resolving power of a telescope is defined as the inverse of the minimum angular separation between two objects that can be just distinguished by the telescope. It is given by the formula: $RP = \frac{D}{1.22 \lambda}$,where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light used. From this relation,it is clear that the resolving power is directly proportional to the diameter of the objective lens $(D)$. Therefore,increasing the diameter of the objective increases the resolving power of the telescope.

Resolving power of a telescope can be increased by increasing

Similar Questions

If the numerical aperture $(NA)$ of a microscope is increased,then its:

$A$ microscope was initially placed in air (refractive index $1$). It is then immersed in oil (refractive index $2$). For a light whose wavelength in air is $\lambda$,calculate the change of the microscope's resolving power due to oil and choose the correct option.

How to increase the resolving power of a telescope and a microscope?

For a given wavelength,telescopes with large aperture objectives are used for:

Assertion $(A):$ To increase the resolving power of a telescope,the aperture $(a)$ of the objective lens should be large.
Reason $(R):$ The resolving power of a telescope is given by $\frac{a}{1.22 \lambda}$.

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