Resistance of 0.2 , M solution of an electrol | vedclass

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(A) For the $0.2 \, M$ solution:$R_1 = 50 \, \Omega$,$\kappa_1 = 1.4 \, S \, m^{-1}$.Cell constant $G^* = R_1 	imes \kappa_1 = 50 	imes 1.4 = 70 \,

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$5 	imes 10^{-4}$

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(A) For the $0.2 \, M$ solution:$R_1 = 50 \, \Omega$,$\kappa_1 = 1.4 \, S \, m^{-1}$.Cell constant $G^* = R_1 	imes \kappa_1 = 50 	imes 1.4 = 70 \, m^{-1}$.For the $0.5 \, M$ solution:$R_2 = 280 \, \Omega$.Specific conductance $\kappa_2 = \frac{G^*}{R_2} = \frac{70}{280} = 0.25 \, S \, m^{-1}$.Molar conductivity $\Lambda_m = \frac{\kappa_2}{C} = \frac{0.25 \, S \, m^{-1}}{0.5 \, mol \, L^{-1}}$.Convert concentration to $mol \, m^{-3}$: $0.5 \, mol \, L^{-1} = 0.5 	imes 1000 \, mol \, m^{-3} = 500 \, mol \, m^{-3}$.$\Lambda_m = \frac{0.25}{500} = 0.0005 = 5 	imes 10^{-4} \, S \, m^2 \, mol^{-1}$.

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