The relation between K_1 and K_2 for the give | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reactions represent the dissociation of cyanohydrins into carbonyl compounds and $HCN$. Reaction $(1)$ is the dissociation of acetone cyanohyd

Vedclass · Accepted Answer

$K_1 > K_2$

Vedclass · Answer

(B) The reactions represent the dissociation of cyanohydrins into carbonyl compounds and $HCN$. Reaction $(1)$ is the dissociation of acetone cyanohydrin,and reaction $(2)$ is the dissociation of acetaldehyde cyanohydrin. The equilibrium constant for the formation of cyanohydrin is $K_{form} = \frac{1}{K_{dissociation}}$. Aldehydes are more reactive towards nucleophilic addition than ketones due to less steric hindrance and electronic factors. Therefore,the formation constant for acetaldehyde cyanohydrin is greater than that for acetone cyanohydrin. This implies $K_{form(acetaldehyde)} > K_{form(acetone)}$. Since $K_{form} = \frac{1}{K_{dissociation}}$,we have $\frac{1}{K_2} > \frac{1}{K_1}$,which leads to $K_1 > K_2$.

The relation between $K_1$ and $K_2$ for the given equilibrium reactions is:

Similar Questions

Arrange the following in increasing order of their acidic strength:

In the given reaction,$[X]$ will be:

The amount (in $mol$) of bromoform $(CHBr_{3})$ produced when $1.0 \ mol$ of acetone reacts completely with $1.0 \ mol$ of bromine in the presence of aqueous $NaOH$ is $......$

Grignard reagent is added to .......

The light yellow compound produced when acetone reacts with iodine and alkali is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module