The Reimer-Tiemann reaction introduces an aldehyde group onto the aromatic ring of phenol,ortho to the hydroxyl group. This reaction involves electrophilic aromatic substitution. This is a general method for the synthesis of substituted salicylaldehydes as depicted below.
$1.$ Which one of the following reagents is used in the above reaction?
$A.$ aq. $NaOH + CH_3Cl$
$B.$ aq. $NaOH + CH_2Cl_2$
$C.$ aq. $NaOH + CHCl_3$
$D.$ aq. $NaOH + CCl_4$
$2.$ The electrophile in this reaction is
$A.$ $:CHCl$
$B.$ $^{+}CHCl_2$
$C.$ $:CCl_2$
$D.$ $CCl_3^{-}$
$3.$ The structure of the intermediate $I$ is
(See provided image for structures $A$,$B$,$C$,$D$)
Give the answer for questions $1, 2$ and $3.$

  • A
    $A, D, B$
  • B
    $C, C, A$
  • C
    $C, C, B$
  • D
    $D, A, B$

Explore More

Similar Questions

Assertion : Reimer-Tiemann reaction of phenol with $CCl_4$ in $NaOH$ at $340 \ K$ gives salicylic acid as the major product. Reason : The reaction occurs through intermediate formation of dichlorocarbene.

Identify the reaction shown below:
$C_6H_5OH + CH_2O \xrightarrow{\text{acid or base}} \text{o-hydroxybenzyl alcohol} + \text{p-hydroxybenzyl alcohol}$

Difficult
View Solution

What is the correct order of $K_a$ values for the given compounds?

Phenol $\xrightarrow[\Delta ]{Zn} A$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} B$ $\xrightarrow[\Delta ]{KMnO_4/OH^{-}} C$
The product $C$ is

Difficult
View Solution

Match the following $pKa$ values:
Acid$pKa$
$(a)$ Phenol$(i)$ $16$
$(b)$ $p$-Nitrophenol$(ii)$ $0.78$
$(c)$ Ethanol$(iii)$ $10$
$(d)$ Picric acid$(iv)$ $7.1$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo