Regarding $F^{-}$ and $Cl^{-}$,which of the following statements is/are correct?
$(i)$ $Cl^{-}$ can give up an electron more easily than $F^{-}$
$(ii)$ $Cl^{-}$ is a better reducing agent than $F^{-}$
$(iii)$ $Cl^{-}$ is smaller in size than $F^{-}$
$(iv)$ $F^{-}$ can be oxidized more readily than $Cl^{-}$

  • A
    $(i)$ and $(ii)$
  • B
    $(i), (ii)$ and $(iv)$
  • C
    $(iii)$ and $(iv)$
  • D
    Only $(i)$

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The first $\left( \Delta_{i}H_{1} \right)$ and the second $\left( \Delta_{i}H_{2} \right)$ ionization enthalpies (in $kJ \ mol^{-1}$) and the $\left( \Delta_{eg}H \right)$ electron gain enthalpy (in $kJ \ mol^{-1}$) of a few elements are given below:
Elements $\left( \Delta_{i}H_{1} \right)$ $\left( \Delta_{i}H_{2} \right)$ $\left( \Delta_{eg}H \right)$
$I$ $520$ $7300$ $-60$
$II$ $419$ $3051$ $-48$
$III$ $1681$ $3374$ $-328$
$IV$ $1008$ $1846$ $-295$
$V$ $2372$ $8581$ $+48$
$VI$ $738$ $1451$ $-40$

Which of the above elements is likely to be:
$(a)$ the least reactive element.
$(b)$ the most reactive metal.
$(c)$ the most reactive non-metal.
$(d)$ the least reactive non-metal.
$(e)$ the metal which can form a stable binary halide of the formula $MX_{2}$ ($X =$ halogen).
$(f)$ the metal which can form a predominantly stable covalent halide of the formula $MX$ ($X =$ halogen)?

Which of the following pairs has elements containing the same number of electrons in the outermost orbit?

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