Reduction of which compound gives an opticall | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reduction of $Butanone$ $(CH_3COCH_2CH_3)$ using a reducing agent like $NaBH_4$ or $LiAlH_4$ yields $Butan-2-ol$ $(CH_3CH(OH)CH_2CH_3)$.In $Bu

Vedclass · Accepted Answer

Butanone

Vedclass · Answer

(B) The reduction of $Butanone$ $(CH_3COCH_2CH_3)$ using a reducing agent like $NaBH_4$ or $LiAlH_4$ yields $Butan-2-ol$ $(CH_3CH(OH)CH_2CH_3)$.In $Butan-2-ol$,the carbon atom attached to the $-OH$ group is bonded to four different groups: $-H$,$-OH$,$-CH_3$,and $-CH_2CH_3$.Since this carbon is a chiral center,$Butan-2-ol$ exists as a pair of enantiomers and is optically active.The other options yield primary alcohols $(Butan-1-ol)$ which are achiral.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

Reduction of which compound gives an optically active alcohol?

Similar Questions

Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

Explain the oxidation of aldehydes and ketones by strong oxidizing agents.

Positive Tollen's test is observed for

Among the following,the compounds which can be reduced with formaldehyde and conc. $aq.$ $KOH$ are $.....$

The reaction $CH_3CHO \xrightarrow[Zn(Hg)/Conc. HCl]{[H]} CH_3CH_3$ is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module