Reduction of acetyl chloride with H_2 in the | vedclass

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(D) The reduction of an acid chloride with $H_2$ in the presence of $Pd$ supported on $BaSO_4$ (poisoned with sulfur or quinoline) is known as the Ros

Vedclass · Accepted Answer

$CH_3CHO$

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(D) The reduction of an acid chloride with $H_2$ in the presence of $Pd$ supported on $BaSO_4$ (poisoned with sulfur or quinoline) is known as the Rosenmund reduction.This reaction specifically reduces the acid chloride to an aldehyde.For acetyl chloride $(CH_3COCl)$:$CH_3COCl + H_2 \xrightarrow{Pd/BaSO_4} CH_3CHO + HCl$Thus,the product is acetaldehyde $(CH_3CHO)$.

Reduction of acetyl chloride with $H_2$ in the presence of $Pd$ gives:

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