The reaction sequence is as follows:Benzene + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The reaction of benzene with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction,which produces acetophen

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) $1$. The reaction of benzene with $CH_3COCl$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts acylation reaction,which produces acetophenone $(A)$ as the product $(C_6H_5COCH_3)$.$2$. The conversion of acetophenone to ethylbenzene $(C_6H_5CH_2CH_3)$ involves the reduction of the carbonyl group $(>C=O)$ to a methylene group $(>CH_2)$.$3$. The reagents listed are all standard methods for the reduction of carbonyl compounds to alkanes:- $HI / 	ext{Red } P$ is a strong reducing agent that reduces carbonyl groups to methylene groups.- $Zn-Hg / HCl$ is the reagent for Clemmensen reduction,which reduces ketones to alkanes.- $NH_2-NH_2 / \overset{\Theta}{O}H / \Delta$ is the reagent for Wolff-Kishner reduction,which also reduces ketones to alkanes.$4$. Since all three reagents can perform this transformation,the correct answer is 'All of the above'.

The reaction sequence is as follows:
Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.
Reagent $(x)$ can be:

Similar Questions

The increasing order of the equilibrium constant for the formation of a hydrate from the following compounds is:

$A$ mixture of benzaldehyde and formaldehyde on heating with aqueous $NaOH$ solution gives :-

Acetaldehyde when treated with dilute $NaOH$ gives:

Which compound does not form iodoform with alkali and iodine?

Which of the following will be dehydrated most readily in alkaline medium?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reaction sequence is as follows:Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.Reagent $(x)$ can be: