Acetaldehyde when treated with dilute $NaOH$ gives:

Explain the Cannizzaro reaction.

Identify compound $A$ from the following reaction:
$A + C_2H_5MgBr$ $\xrightarrow[ether]{dry} B$ $\xrightarrow{H_3O^{+}} 3-\text{methylpentan}-3-\text{ol}$

How will you convert butan$-2-$one to propanoic acid?

The structure of product $C$,formed by the following sequence of reactions is :
$CH_3COOH + SOCl_2$ $\longrightarrow A$ $\xrightarrow[AlCl_3]{Benzene} B$ $\xrightarrow[H^{+}]{KCN} C$

Match the following reactions in Column-$1$ with their products in Column-$2$.

Column-$1$ (Reaction)	Column-$2$ (Product)
$A$. Benzaldehyde + $Zn-Hg/HCl$	$I$. Cyclohexanol
$B$. Benzoyl chloride + $H_2/Pd-BaSO_4$	$II$. Benzyl alcohol
$C$. Cyclohexanone + $NH_2NH_2/KOH$	$III$. Toluene
	$IV$. Benzaldehyde
	$V$. Cyclohexane

The correct match is: