Reaction of thionyl chloride with white phosp | vedclass

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Question

(B) The reaction of white phosphorus $(P_4)$ with thionyl chloride $(SOCl_2)$ is given by: $P_4 + 8 SOCl_2 \rightarrow 4 PCl_3 + 4 SO_2 + 2 S_2Cl_2$.

Vedclass · Accepted Answer

$PCl_3$ and $H_3PO_3$

Vedclass · Answer

(B) The reaction of white phosphorus $(P_4)$ with thionyl chloride $(SOCl_2)$ is given by: $P_4 + 8 SOCl_2 \rightarrow 4 PCl_3 + 4 SO_2 + 2 S_2Cl_2$. Thus,compound $[A]$ is $PCl_3$. Hydrolysis of $PCl_3$ yields phosphorous acid $(H_3PO_3)$: $PCl_3 + 3 H_2O \rightarrow H_3PO_3 + 3 HCl$. $H_3PO_3$ is a dibasic acid because it contains two $P-OH$ bonds. Therefore,$[A]$ is $PCl_3$ and $[B]$ is $H_3PO_3$.

Reaction of thionyl chloride with white phosphorus forms a compound $[A]$,which on hydrolysis gives $[B]$,a dibasic acid. $[A]$ and $[B]$ are respectively

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