Reaction of propanamide with ethanolic sodium | vedclass

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Question

(B) The reaction of an amide with bromine $(Br_2)$ in the presence of an aqueous or ethanolic solution of a strong base like sodium hydroxide $(NaOH)$

Vedclass · Accepted Answer

Ethylamine

Vedclass · Answer

(B) The reaction of an amide with bromine $(Br_2)$ in the presence of an aqueous or ethanolic solution of a strong base like sodium hydroxide $(NaOH)$ is known as the Hofmann bromamide degradation reaction.In this reaction,the amide is converted into a primary amine containing one carbon atom less than the original amide.The reaction for propanamide $(CH_3CH_2CONH_2)$ is:$CH_3CH_2CONH_2 + Br_2 + 4NaOH \rightarrow CH_3CH_2NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$As shown in the reaction,propanamide ($3$ carbons) yields ethylamine ($2$ carbons).

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

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