Reaction of benzene with $Me_{3}CCOCl$ in the presence of anhydrous $AlCl_{3}$ gives:

  • A
    $Ph-N(O)=CMe_{3}$
  • B
    $Ph-CMe_{3}$
  • C
    $p-Me_{3}C-C_{6}H_{4}-COCMe_{3}$
  • D
    $Ph-COCMe_{3} \cdot AlCl_{3}$

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