Ratio of translational degrees of freedom to rotational degrees of freedom of a polyatomic linear gas molecule is

Consider two ideal diatomic gases $A$ and $B$ at some temperature $T$. Molecules of the gas $A$ are rigid,and have a mass $m$. Molecules of the gas $B$ have an additional vibrational mode,and have a mass $\frac{m}{4}$. The ratio of the specific heats $(C_{v}^{A}$ and $C_{v}^{B})$ of gas $A$ and $B$,respectively,is

$A$ diatomic gas consisting of rigid molecules is at a temperature of $87^{\circ} C$. If the moment of inertia of the rotating diatomic rigid molecule is $2.76 \times 10^{-46} kg \cdot m^2$,then the rms angular speed of the molecule is (Boltzmann constant $= 1.38 \times 10^{-23} J \cdot K^{-1}$)

State and explain the law of equipartition of energy.

Write the degree of freedom for a diatomic rigid rotator.

What will be the average value of energy for a monoatomic gas in thermal equilibrium at temperature $T$?