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(A) The intensity $I$ of a wave is directly proportional to the square of its amplitude $A$,i.e.,$I \propto A^2$.Therefore,the ratio of maximum intens

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$5 : 4$

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(A) The intensity $I$ of a wave is directly proportional to the square of its amplitude $A$,i.e.,$I \propto A^2$.Therefore,the ratio of maximum intensity to minimum intensity is given by $\frac{I_{\max}}{I_{\min}} = \left( \frac{A_{\max}}{A_{\min}} \right)^2$.Given that $\frac{I_{\max}}{I_{\min}} = \frac{25}{16}$.Substituting this into the equation: $\left( \frac{A_{\max}}{A_{\min}} \right)^2 = \frac{25}{16}$.Taking the square root on both sides: $\frac{A_{\max}}{A_{\min}} = \sqrt{\frac{25}{16}} = \frac{5}{4}$.Thus,the ratio of maximum to minimum amplitude is $5 : 4$.

The ratio of maximum to minimum intensity in an interference pattern is $25 : 16$. Calculate the ratio of maximum to minimum amplitude.

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