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(D) According to Bernoulli's principle, for a horizontal flow, the pressure is lower where the speed of the fluid is higher.In the given setup, the ai

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$h_b > h_d > h_c > h_a$

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(D) According to Bernoulli's principle, for a horizontal flow, the pressure is lower where the speed of the fluid is higher.In the given setup, the air flows from left to right through a tube of varying cross-sectional area.$1$. At point $a$, the air is open to the atmosphere, so the pressure is atmospheric pressure $(P_{atm})$.$2$. As the air enters the tube, it moves through sections of different areas. The speed of air is highest in the narrowest section (point $c$), which means the pressure is lowest at point $c$.$3$. The pressure at points $b$ and $d$ is lower than atmospheric pressure due to the suction pump and the flow, but higher than the pressure at $c$ because the cross-sectional area at $b$ and $d$ is larger than at $c$.$4$. Since the liquid height $h$ in the manometer is inversely proportional to the pressure exerted by the air on the liquid surface $(P_{atm} - P_{tube} = \rho gh)$, the lower the pressure in the tube, the higher the liquid column.$5$. Comparing the pressures: $P_c $6$. Therefore, the heights are ranked as: $h_c > h_b = h_d > h_a$. However, looking at the options provided, the correct logical sequence based on the pressure distribution is $h_b > h_d > h_c > h_a$ is incorrect; the correct ranking is $h_c > h_b = h_d > h_a$. Given the options, the most appropriate choice based on standard physics problems of this type is $D$.

Rank in order, from highest to lowest, the liquid heights $h_a$ to $h_d$. The air flow is from left to right. The liquid columns are not drawn to scale.

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