Ram divided 2189 into three parts such that t | vedclass

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(B) Let the three parts be $a, b,$ and $c$. According to the problem,the simple interest on each part is equal.$\frac{a 	imes 4 	imes 1}{100} = \fra

Vedclass · Accepted Answer

$398$

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(B) Let the three parts be $a, b,$ and $c$. According to the problem,the simple interest on each part is equal.$\frac{a 	imes 4 	imes 1}{100} = \frac{b 	imes 4 	imes 2}{100} = \frac{c 	imes 4 	imes 3}{100}$By simplifying,we get:$4a = 8b = 12c$Dividing by $4$,we get:$a = 2b = 3c = k$ (where $k$ is a constant).Therefore,$a = k, b = k/2, c = k/3$.To find the ratio,multiply by $6$:$a:b:c = 6:3:2$.The sum of the parts is $6x + 3x + 2x = 11x = 2189$.$x = 2189 / 11 = 199$.The smallest part corresponds to $2x$:Smallest part $= 2 	imes 199 = Rs. 398$.

Ram divided $2189$ into three parts such that the simple interest on them after $1, 2,$ and $3$ years respectively is equal. The rate of simple interest is $4\%$ per annum in all cases. The smallest part is (in $Rs.$):

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