Propene is the product obtained by the dehydr | vedclass

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(B) Dehydrogenation of alcohols involves the removal of hydrogen to form alkenes or carbonyl compounds. When $2-$propanol $(CH_3-CH(OH)-CH_3)$ is pass

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$1-$propanol

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(B) Dehydrogenation of alcohols involves the removal of hydrogen to form alkenes or carbonyl compounds. When $2-$propanol $(CH_3-CH(OH)-CH_3)$ is passed over heated copper at $573 \ K$,it undergoes dehydrogenation to form propanone (a ketone). However,if we consider the dehydration of $1-$propanol or $2-$propanol,propene is formed. Specifically,the question asks for dehydrogenation,but in the context of standard chemistry problems,the dehydration of $1-$propanol $(CH_3-CH_2-CH_2-OH)$ using catalysts like $Al_2O_3$ at high temperatures yields propene $(CH_3-CH=CH_2)$. Given the options,$1-$propanol is the precursor that leads to propene via elimination reactions.

Propene is the product obtained by the dehydrogenation of

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