Propene,CH_3-CH=CH_2 can be converted to 1-pr | vedclass

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(B) The conversion of propene to $1-propanol$ is an anti-Markovnikov hydration reaction,which is achieved via hydroboration-oxidation.Step $1$: Hydrob

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$B_2H_6$ and alkaline $H_2O_2$

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(B) The conversion of propene to $1-propanol$ is an anti-Markovnikov hydration reaction,which is achieved via hydroboration-oxidation.Step $1$: Hydroboration: $3CH_3-CH=CH_2 + \frac{1}{2}B_2H_6 \rightarrow (CH_3-CH_2-CH_2)_3B$Step $2$: Oxidation: $(CH_3-CH_2-CH_2)_3B + 3H_2O_2 \xrightarrow{OH^-} 3CH_3-CH_2-CH_2-OH + B(OH)_3$Thus,the reagents $B_2H_6$ and alkaline $H_2O_2$ are ideal for this conversion.

Propene,$CH_3-CH=CH_2$ can be converted to $1-propanol$ by oxidation. Which set of reagents among the following is ideal to effect the conversion?

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