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(B) The reaction is a Nucleophilic Aromatic Substitution $(S_NAr)$ reaction.In $1$-chloro-$2,4$-dinitrobenzene,the chlorine atom is at the $ortho$ pos

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$1-$methoxy$-2,4-$dinitrobenzene

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(B) The reaction is a Nucleophilic Aromatic Substitution $(S_NAr)$ reaction.In $1$-chloro-$2,4$-dinitrobenzene,the chlorine atom is at the $ortho$ position with respect to one $-NO_2$ group and at the $para$ position with respect to the other $-NO_2$ group.Electron-withdrawing groups (like $-NO_2$) at $ortho$ and $para$ positions activate the ring towards nucleophilic attack by stabilizing the Meisenheimer complex intermediate.Since both $-NO_2$ groups are at $ortho$ and $para$ positions relative to the chlorine atom,the chlorine atom is highly activated and is replaced by the methoxide ion $(CH_3O^-)$ to form $1$-methoxy-$2,4$-dinitrobenzene.

What will be the product of the following reaction?
$1$-chloro-$2,4$-dinitrobenzene + $CH_3ONa \xrightarrow{\Delta} \text{Product}$

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What will be the product of the following reaction?$1$-chloro-$2,4$-dinitrobenzene + $CH_3ONa \xrightarrow{\Delta} \text{Product}$