What is the product of the following reaction?

Amongst the following,the total number of compounds soluble in aqueous $NaOH$ at room temperature is:
$(I)$ Benzaldehyde
$(II)$ $1$-Naphthol
$(III)$ $4$-(Dimethylamino)phenol
$(IV)$ $4$-Methylphenol
$(V)$ Benzoic acid
$(VI)$ $N,N$-Dimethylcyclohexanamine
$(VII)$ $1$-Naphthoic acid
$(VIII)$ $1,4$-Di-tert-butylbenzene
$(IX)$ $1$-Naphthylmethanol

Ester and acetamide are distinguished by

In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$

Saponification (basic hydrolysis) of $C_6H_5-CO-^{18}OCH_3$ will yield. [$^{18}O$ = mass $-18$ isotope of oxygen]

Product $(A)$ and $(B)$ respectively in the above reaction are