The product of the reaction CH_3O-CH_2-CH(OCH | vedclass

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(C) When $1,2,3$-trimethoxypropane reacts with excess $HI$,the ether bonds are cleaved first to produce glycerol $(CH_2OH-CHOH-CH_2OH)$ and methyl iod

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$2-$iodopropane

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(C) When $1,2,3$-trimethoxypropane reacts with excess $HI$,the ether bonds are cleaved first to produce glycerol $(CH_2OH-CHOH-CH_2OH)$ and methyl iodide $(CH_3I)$.Glycerol then reacts with excess $HI$ through a series of steps:$CH_2OH-CHOH-CH_2OH$ $\xrightarrow{3HI} [CH_2I-CHI-CH_2I]$ $\xrightarrow{-I_2} CH_2=CH-CH_2I$ $\xrightarrow{HI} [CH_3-CHI-CH_2I]$ $\xrightarrow{-I_2} CH_3-CH=CH_2$ $\xrightarrow{HI} CH_3-CHI-CH_3$.The final stable product is $2$-iodopropane (isopropyl iodide).

The product of the reaction $CH_3O-CH_2-CH(OCH_3)-CH_2-OCH_3 \xrightarrow{HI(excess)}$ is:

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