The product of the reaction shown is:

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(A) The reaction is the catalytic hydrogenation of $(E)-but-2-ene-2,3-d_2$ (trans-isomer) using $H_2/Pt$. Catalytic hydrogenation is a $syn$-addition

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Racemic

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(A) The reaction is the catalytic hydrogenation of $(E)-but-2-ene-2,3-d_2$ (trans-isomer) using $H_2/Pt$. Catalytic hydrogenation is a $syn$-addition process. When $H_2$ adds to the $(E)$-isomer in a $syn$ fashion,it results in the formation of a pair of enantiomers. Since the starting material is achiral and the addition is $syn$,the product obtained is a racemic mixture of the two enantiomers.

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