What is the product of the following reaction | vedclass

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(A) The given reaction is the Hofmann rearrangement of phthalimide. Phthalimide reacts with $NaOBr$ (which is $NaOH + Br_2$) followed by acid hydrolys

Vedclass · Accepted Answer

$2-$aminobenzoic acid

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(A) The given reaction is the Hofmann rearrangement of phthalimide. Phthalimide reacts with $NaOBr$ (which is $NaOH + Br_2$) followed by acid hydrolysis $(H^{\oplus})$. This reaction converts the amide group $(-CONH_2)$ into an amine group $(-NH_2)$ with the loss of one carbon atom as $CO_2$. In the case of phthalimide,the cyclic imide structure undergoes rearrangement to form anthranilic acid ($2$-aminobenzoic acid).

What is the product of the following reaction?

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