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(A) The reaction involves the electrophilic addition of $Br_2$ to the alkene. First,a cyclic bromonium ion intermediate is formed across the double bo

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(A) The reaction involves the electrophilic addition of $Br_2$ to the alkene. First,a cyclic bromonium ion intermediate is formed across the double bond. Then,the intramolecular nucleophilic attack by the hydroxyl group $(-OH)$ on the more substituted carbon of the bromonium ion occurs,leading to the formation of a $6$-membered cyclic ether ring. This process is known as halocyclization. Based on the structure of the starting material,the product $(A)$ is the cyclic ether shown in option $A$.

Product $(A)$ is

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