The reaction is given as:Naphthalene + Oxalyl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads

Vedclass · Accepted Answer

Acenaphthene

Vedclass · Answer

(C) $1$. The reaction of naphthalene with oxalyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts acylation reaction.$2$. This reaction leads to the formation of acenaphthenequinone,which is the intermediate $[X]$.$3$. The subsequent reduction of the carbonyl groups in $[X]$ using $Na-Hg$ and $HCl$ (Clemmensen reduction) converts the two ketone groups into methylene groups $(-CH_2-)$.$4$. This reduction process yields acenaphthene as the final product $[Y]$.

The reaction is given as:
Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$
Product $Y$ is:

Similar Questions

(no ring substitution) Product $(A)$ is

Which of the following compounds are aromatic?

Sodium benzoate on heating with sodalime gives:

$C_6H_6$ $\xrightarrow{HNO_3, H_2SO_4} X$ $\xrightarrow{Cl_2, FeCl_3} Y$. In the above sequence,$Y$ is:

During the mixed acid nitration of benzene,concentrated $HNO_3$ behaves like:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The reaction is given as:Naphthalene + Oxalyl chloride $\xrightarrow{AlCl_3} [X]$ $\xrightarrow{Na-Hg, HCl \text{ (excess)}} [Y]$Product $Y$ is: