The product (P) is formed by the reaction of | vedclass

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(B) When a ketone (like cyclohexanone) reacts with two equivalents of an alcohol (like ethanol) in the presence of an acid catalyst $(H^+)$,it forms a

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Acetal

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(B) When a ketone (like cyclohexanone) reacts with two equivalents of an alcohol (like ethanol) in the presence of an acid catalyst $(H^+)$,it forms an acetal.The reaction proceeds in two steps:$1$. The ketone reacts with one equivalent of alcohol to form a hemiacetal.$2$. The hemiacetal then reacts with a second equivalent of alcohol to form an acetal.Since the reaction uses $2$ equivalents of ethanol,the final product $(P)$ is an acetal.

The product $(P)$ is formed by the reaction of cyclohexanone with $2$ equivalents of ethanol in the presence of an acid catalyst. The reaction is given as:
Cyclohexanone $+ 2EtOH \xrightarrow{H^+} (P)$
Product $(P)$ is:

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The product $(P)$ is formed by the reaction of cyclohexanone with $2$ equivalents of ethanol in the presence of an acid catalyst. The reaction is given as:Cyclohexanone $+ 2EtOH \xrightarrow{H^+} (P)$Product $(P)$ is: