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(B) The starting material is $2(5H)$-furanone. Step $1$: Reduction with $NaBH_4$ selectively reduces the carbonyl group to a hydroxyl group,yielding $

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furan

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(B) The starting material is $2(5H)$-furanone. Step $1$: Reduction with $NaBH_4$ selectively reduces the carbonyl group to a hydroxyl group,yielding $2,5$-dihydrofuran-$2$-ol (compound $(A)$). Step $2$: Acid-catalyzed dehydration $(H^+/\Delta)$ of the cyclic hemiacetal $(A)$ leads to the formation of furan (compound $(B)$) by the elimination of a water molecule and restoration of aromaticity.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

The product $(B)$ of the reaction is:

Similar Questions

Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

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