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(B) $1$. The reaction of cyclohexyl methyl ketone with $PCl_5$ at $0^{\circ}C$ results in the formation of a gem-dichloride,specifically $1,1$-dichlor

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Ethynylcyclohexane

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(B) $1$. The reaction of cyclohexyl methyl ketone with $PCl_5$ at $0^{\circ}C$ results in the formation of a gem-dichloride,specifically $1,1$-dichloroethylcyclohexane,which is product $(A)$.$2$. The subsequent treatment of $(A)$ with $3 \ NaNH_2$ in mineral oil followed by an acidic workup $(H^{\oplus})$ leads to a double dehydrohalogenation reaction.$3$. The $1,1$-dichloroethylcyclohexane undergoes elimination of two molecules of $HCl$ to form the terminal alkyne,ethynylcyclohexane,which is product $(B)$.

The product $(B)$ is:

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