The probability that a man will be alive 25 y | vedclass

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(B) Let $A$ be the event that the man is alive after $25$ years and $B$ be the event that his wife is alive after $25$ years.Given: $P(A) = 0.3$ and $

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$0.18$

Vedclass · Answer

(B) Let $A$ be the event that the man is alive after $25$ years and $B$ be the event that his wife is alive after $25$ years.Given: $P(A) = 0.3$ and $P(B) = 0.4$.The probability that the wife will not be alive after $25$ years is $P(\bar{B}) = 1 - P(B) = 1 - 0.4 = 0.6$.We need to find the probability that only the man will be alive,which means the man is alive $AND$ the wife is not alive.Required probability $= P(A \cap \bar{B}) = P(A) 	imes P(\bar{B}) = 0.3 	imes 0.6 = 0.18$.

The probability that a man will be alive $25$ years hence is $0.3$ and the probability that his wife will be alive $25$ years hence is $0.4$. Find the probability that $25$ years hence,only the man will be alive.

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