Primary and secondary alcohols on action of reduced copper give

$1-Methylcyclohexene$ $\xrightarrow[\text{cold}]{alkaline\,KMnO_4} A$ $\xrightarrow[CH_3COOH]{CrO_3} B$
$A$ and $B$ are

Match the reactants given in Column-$I$ with the products formed in Column-$II$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. $ROH + SOCl_2$	$i$. $RBr + NaHSO_4 + H_2O$
$B$. $ROH + PCl_5$	$ii$. $3RX + H_3PO_3$
$C$. $3ROH + PX_3$	$iii$. $RCl + SO_2 + HCl$
$D$. $ROH + NaBr + H_2SO_4$	$iv$. $RCl + POCl_3 + HCl$

An alcohol of formula $C_9H_{12}O$ reacts with $Na_2Cr_2O_7$ to form a compound having formula $C_9H_{10}O$. The original alcohol might be

Statement-$1$ : Secondary $\&$ Tertiary alcohols can be distinguished by Lucas reagent.
Statement-$2$ : Secondary $\&$ Tertiary alcohols can be distinguished by dichromate test.

Glycerol is used: