Pressure gradient has the same dimension as t | vedclass

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Question

(D) The dimension of pressure gradient is calculated as: $\frac{P}{x} = \frac{[M L^{-1} T^{-2}]}{[L]} = [M L^{-2} T^{-2}]$.$1$. Velocity gradient: $\f

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None of these

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(D) The dimension of pressure gradient is calculated as: $\frac{P}{x} = \frac{[M L^{-1} T^{-2}]}{[L]} = [M L^{-2} T^{-2}]$.$1$. Velocity gradient: $\frac{v}{x} = \frac{[L T^{-1}]}{[L]} = [T^{-1}]$.$2$. Potential gradient: $\frac{V}{x} = \frac{[M L^2 T^{-3} A^{-1}]}{[L]} = [M L T^{-3} A^{-1}]$.$3$. Energy gradient: $\frac{E}{x} = \frac{[M L^2 T^{-2}]}{[L]} = [M L T^{-2}]$.Comparing these,the dimension of pressure gradient does not match any of the given options. Therefore,the correct option is $(d)$.

Pressure gradient has the same dimension as that of

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