Predict the product C obtained in the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the reaction of $1-$butyne with $HCl$,Markovnikov addition occurs to form $2-$chloro-$1-$butene $(B)$.Subsequent addition of $HI$ to $B$ also f

Vedclass · Accepted Answer

$CH_3-CH_2-C(I)(Cl)-CH_3$

Vedclass · Answer

(C) In the reaction of $1-$butyne with $HCl$,Markovnikov addition occurs to form $2-$chloro-$1-$butene $(B)$.Subsequent addition of $HI$ to $B$ also follows Markovnikov's rule,where the iodine atom attaches to the carbon already containing the chlorine atom,resulting in $2-$chloro-$2-$iodobutane $(C)$.Reaction:$CH_3-CH_2-C \equiv CH + HCl \rightarrow CH_3-CH_2-CCl=CH_2 (B)$$CH_3-CH_2-CCl=CH_2 + HI \rightarrow CH_3-CH_2-C(I)(Cl)-CH_3 (C)$

Predict the product $C$ obtained in the following reaction of $1-$butyne: $CH_3-CH_2-C \equiv CH + HCl$ $\rightarrow B$ $\xrightarrow{HI} C$

Similar Questions

$2-$butyne is reduced to $trans-but-2-ene$ using:

$CH_3 - C \equiv C - CH_3 \xrightarrow[CH_3COOH]{BH_3, THF} \text{Major product}$

Which one of the following carbonyl compounds cannot be prepared by addition of water on an alkyne in the presence of $HgSO_4$ and $H_2SO_4$?

What is the product $A$ in the given reaction?
$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$

Explain: "Why do alkyne compounds undergo electrophilic addition reactions?"

Vedclass Test Series

Exam Paper Generator

Online Exam Module