Predict the correct product when $Cl_2$ is passed through a $H^{18}O-^{18}OH$ solution.
- A$H^{+} + Cl^{-} + ^{18}O_2$ (both oxygen atoms are $^{18}O$)
- B$HO^{18}Cl$ and $HCl^{18}O_2$ (all oxygen atoms are $^{18}O$)
- C$HCl^{18}O_4$ and $HCl$ (all oxygen atoms are $^{18}O$)
- D$Cl_2^{18}O$ and $H_2^{18}O$ (all oxygen atoms are $^{18}O$)
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$H_2O_2$ acts as an oxidising agent in
Easy
View SolutionWith reference to the redox properties of hydrogen peroxide $(H_2O_2)$,which of these reactions are feasible?
$(I)$ $2Fe^{2+} + 2H^{+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2H_2O$
$(II)$ $2MnO_4^{-} + 6H^{+} + 5H_2O_2 \longrightarrow 2Mn^{2+} + 8H_2O + 5O_2$
$(III)$ $2Fe^{2+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2OH^{-}$
$(IV)$ $2MnO_4^{-} + 3H_2O_2 \longrightarrow 2MnO_2 + 2H_2O + 3O_2 + 2OH^{-}$
$(I)$ $2Fe^{2+} + 2H^{+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2H_2O$
$(II)$ $2MnO_4^{-} + 6H^{+} + 5H_2O_2 \longrightarrow 2Mn^{2+} + 8H_2O + 5O_2$
$(III)$ $2Fe^{2+} + H_2O_2 \longrightarrow 2Fe^{3+} + 2OH^{-}$
$(IV)$ $2MnO_4^{-} + 3H_2O_2 \longrightarrow 2MnO_2 + 2H_2O + 3O_2 + 2OH^{-}$
The volume (in $mL$) of $10$ volume $H_2O_2$ solution required to completely react with $200 \ mL$ of $0.4 \ M \ KMnO_4$ solution in acidic medium is
Two litres of $15$ volume solution of $H_2O_2$ on complete decomposition liberated $x$ litres of $O_2$ at $STP$. What is the value of $x$ (in litres)?
$H_2O_2$ is obtained by which of the following?
MediumAIIMS 2019
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