Predict the correct intermediate and product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the presence of $HgSO_4$ and $H_2SO_4$,alkynes undergo hydration following Markovnikov's rule. Propyne $(CH_3-C \equiv CH)$ reacts with water t

Vedclass · Accepted Answer

$A: CH_3-C(OH)=CH_2, B: CH_3-C(=O)-CH_3$

Vedclass · Answer

(C) In the presence of $HgSO_4$ and $H_2SO_4$,alkynes undergo hydration following Markovnikov's rule. Propyne $(CH_3-C \equiv CH)$ reacts with water to form an unstable enol intermediate,$CH_3-C(OH)=CH_2$ $(A)$. This enol then undergoes tautomerization to form the more stable keto form,propanone $CH_3-C(=O)-CH_3$ $(B)$. $CH_3-C \equiv CH + H_2O \xrightarrow{Hg^{2+}/H^{+}} [CH_3-C(OH)=CH_2] 	o CH_3-C(=O)-CH_3$

Predict the correct intermediate and product in the following reaction: $CH_3-C \equiv CH \xrightarrow[HgSO_4]{H_2O, H_2SO_4} \text{Intermediate } (A) \to \text{Product } (B)$

Similar Questions

When acetylene reacts with arsenic trichloride in the presence of anhydrous aluminium chloride,it produces

$CH \equiv CH$ $\xrightarrow[H_2SO_4]{H_2O/Hg^{2+}} X$ $\xrightarrow{LiAlH_4} Y$ $\xrightarrow{P_4/Br_2} Z$. Here $Z$ is

The major product obtained from the following reaction is

Which of the following has the shortest $C - C$ bond length?

In the reaction $CH_3-C \equiv C-CH_3 \xrightarrow[(ii) H_2O/Zn]{(i) X} CH_3-CO-CO-CH_3$,what is $X$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module