Potential in the $x-y$ plane is given as $V = 5(x^2 + xy)\, volts$. The electric field at the point $(1, -2)$ will be
Potential in the $x-y$ plane is given as $V = 5(x^2 + xy)\, volts$. The electric field at the point $(1, -2)$ will be
- A
$3j\, V/m$
- B
$-5j\, V/m$
- C
$5j \,V/m$
- D
$-3j \,V/m$
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