The point of intersection of the diagonals of a square is at the origin,and the coordinate axes are drawn along the diagonals. If the side length of the square is $a$,then which of the following is $NOT$ a vertex of the square?

  • A
    $(a\sqrt{2}, 0)$
  • B
    $\left(0, \frac{a}{\sqrt{2}}\right)$
  • C
    $\left(\frac{a}{\sqrt{2}}, 0\right)$
  • D
    $\left(-\frac{a}{\sqrt{2}}, 0\right)$

Explore More

Similar Questions

If a square $ABCD$,where $A(0,0), B(2,0), C(2,2)$ and $D(0,2)$ undergoes the following transformations successively,then the final figure would be a:
$(i)$ $f_1(x, y) \longrightarrow (y, x)$
(ii) $f_2(x, y) \longrightarrow (x+3y, y)$
(iii) $f_3(x, y) \longrightarrow \left(\frac{x-y}{2}, \frac{x+y}{2}\right)$

An insect is resting on the graph paper at a point $A(3, 2)$. Now it starts moving towards the west direction and covers a distance of $4 \ units$,then it turns towards the south and covers a distance of $3 \ units$ to reach point $B$. The polar coordinates of point $B$ will be:

If the Cartesian coordinates of a point are $\left(\frac{-5 \sqrt{3}}{2}, \frac{5}{2}\right)$,then its polar coordinates are

To which point should the origin be shifted in order to eliminate the first-degree terms ($x$ and $y$ terms) from the equation $4x^2 + 9y^2 - 8x + 36y + 4 = 0$?

Two fixed points are $A(a, 0)$ and $B(-a, 0)$. If $\angle A - \angle B = \theta$,then the locus of point $C$ of triangle $ABC$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo