The point of intersection of the diagonals of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the vertices of the square be $A, B, C,$ and $D$. Since the diagonals lie along the coordinate axes and the side length is $a$,the distance fr

Vedclass · Accepted Answer

$(a\sqrt{2}, 0)$

Vedclass · Answer

(A) Let the vertices of the square be $A, B, C,$ and $D$. Since the diagonals lie along the coordinate axes and the side length is $a$,the distance from the origin to each vertex is half the length of the diagonal.The diagonal length $d$ of a square with side $a$ is $a\sqrt{2}$.Thus,the distance from the origin to each vertex is $\frac{a\sqrt{2}}{2} = \frac{a}{\sqrt{2}}$.The vertices are located at $(\frac{a}{\sqrt{2}}, 0), (0, \frac{a}{\sqrt{2}}), (-\frac{a}{\sqrt{2}}, 0),$ and $(0, -\frac{a}{\sqrt{2}})$.Comparing these with the given options,$(a\sqrt{2}, 0)$ is not a vertex.

The point of intersection of the diagonals of a square is at the origin,and the coordinate axes are drawn along the diagonals. If the side length of the square is $a$,which of the following is $NOT$ a vertex of the square?

Similar Questions

If $y = (\cos x^2)^2$,then $\frac{dy}{dx}$ is equal to:

The major product of the following reaction is

In humans,what is the ratio of the number of gametes produced from one male primary sex cell to the number of gametes produced from one female primary sex cell?

For reaction aldehyde in acidic medium reaction of column-$I$ and its derived product in column-$II$ and their product are given in column-$III$. So match accordingly.

The angle of a prism is $A.$ One of its refracting surfaces is silvered. Light rays falling at an angle of incidence $2A$ on the first surface return back through the same path after suffering reflection at the silvered surface. The refractive index $\mu$ of the prism is

Vedclass Test Series

Exam Paper Generator

Online Exam Module