Plot the following points and write the name of the figure obtained by joining them in order:
$P(-3, 2), Q(-7, -3), R(6, -3), S(2, 2)$
$P(-3, 2), Q(-7, -3), R(6, -3), S(2, 2)$
(N/A) $1$. Draw the coordinate axes $X'OX$ and $Y'OY$ on a graph paper.
$2$. Plot the points $P(-3, 2)$,$Q(-7, -3)$,$R(6, -3)$,and $S(2, 2)$ by locating their respective $x$ and $y$ coordinates.
$3$. Join the points in the order $P$ to $Q$,$Q$ to $R$,$R$ to $S$,and $S$ to $P$.
$4$. Observe the figure formed. The side $PS$ is parallel to the side $QR$ because both lie on horizontal lines ($y=2$ and $y=-3$ respectively),but they are of different lengths ($PS = 5$ units,$QR = 13$ units).
$5$. Since one pair of opposite sides is parallel and the other is not,the figure obtained is a trapezium.
$2$. Plot the points $P(-3, 2)$,$Q(-7, -3)$,$R(6, -3)$,and $S(2, 2)$ by locating their respective $x$ and $y$ coordinates.
$3$. Join the points in the order $P$ to $Q$,$Q$ to $R$,$R$ to $S$,and $S$ to $P$.
$4$. Observe the figure formed. The side $PS$ is parallel to the side $QR$ because both lie on horizontal lines ($y=2$ and $y=-3$ respectively),but they are of different lengths ($PS = 5$ units,$QR = 13$ units).
$5$. Since one pair of opposite sides is parallel and the other is not,the figure obtained is a trapezium.
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