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(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6

Vedclass · Accepted Answer

$[Co(NH_3)_3(NO_2)_3]$

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(B) The conductivity of an electrolytic solution depends on the number of ions produced upon dissociation.$1$. $K_2[PtCl_6] \rightarrow 2K^+ + [PtCl_6]^{2-}$ ($3$ ions)$2$. $[Co(NH_3)_3(NO_2)_3] \rightarrow$ No ions (non-ionizable as it is a neutral complex)$3$. $K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}$ ($5$ ions)$4$. $[Cu(NH_3)_4]SO_4 \rightarrow [Cu(NH_3)_4]^{2+} + SO_4^{2-}$ ($2$ ions)Since $[Co(NH_3)_3(NO_2)_3]$ does not produce any ions in solution,it is a poor electrolytic conductor.

Pick out from the following complex compounds,a poor electrolytic conductor in solution.

Similar Questions

The purple color of $KMnO_4$ is due to which of the following?

Which among the following cations will form the lowest stability complex if the ligand remains the same?

Which among the following cations forms the most stable complex with the same ligand?

Arrange the following complexes in the correct increasing order of their electrical conductivity in aqueous solution:
$(I) [Pt(NH_3)_6]Cl_4$
$(II) [Cr(NH_3)_6]Cl_3$
$(III) [Co(NH_3)_4Cl_2]Cl$
$(IV) K_2[PtCl_6]$

The most stable complex among the following is

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