The phosphate radical reacts with ammonium mo | vedclass

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(C) The phosphate radical $(PO_4^{3-})$ reacts with ammonium molybdate $(NH_4)_2MoO_4$ in the presence of concentrated nitric acid $(HNO_3)$ to form a

Vedclass · Accepted Answer

Canary yellow

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(C) The phosphate radical $(PO_4^{3-})$ reacts with ammonium molybdate $(NH_4)_2MoO_4$ in the presence of concentrated nitric acid $(HNO_3)$ to form a canary yellow precipitate of ammonium phosphomolybdate.The chemical reaction is:$H_3PO_4 + 12(NH_4)_2MoO_4 + 21HNO_3 \rightarrow (NH_4)_3PO_4 \cdot 12MoO_3 + 21NH_4NO_3 + 12H_2O$The resulting precipitate,$(NH_4)_3PO_4 \cdot 12MoO_3$,is known as canary yellow precipitate.

The phosphate radical reacts with ammonium molybdate to form a precipitate of which color?

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