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(C) To find the time when they meet again at the starting point, we need to calculate the Least Common Multiple $(LCM)$ of the time taken by each pers

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$16\, 	ext{minutes } 30\, 	ext{seconds}$

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(C) To find the time when they meet again at the starting point, we need to calculate the Least Common Multiple $(LCM)$ of the time taken by each person to complete one round.The times are $18\, 	ext{seconds}$, $22\, 	ext{seconds}$, and $30\, 	ext{seconds}$.Prime factorization:$18 = 2 	imes 3^2$$22 = 2 	imes 11$$30 = 2 	imes 3 	imes 5$$LCM(18, 22, 30) = 2^1 	imes 3^2 	imes 5^1 	imes 11^1 = 2 	imes 9 	imes 5 	imes 11 = 990\, 	ext{seconds}$.Now, convert $990\, 	ext{seconds}$ into minutes:$990 / 60 = 16.5\, 	ext{minutes}$.$0.5\, 	ext{minutes} = 0.5 	imes 60 = 30\, 	ext{seconds}$.Therefore, they will meet again at the starting point after $16\, 	ext{minutes and } 30\, 	ext{seconds}$.

Philip, Tom, and Brad start jogging around a circular field and complete a single round in $18\, \text{seconds}$, $22\, \text{seconds}$, and $30\, \text{seconds}$, respectively. In how much time will they meet again at the starting point?

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