Phenol with Hinsberg's reagent gives

What will be the product of the reaction with $HBr$?

What is the product formed when phenol reacts with concentrated $HNO_3$?

Match the reagents in List-$I$ with the product in List-$II$ obtained from phenol.

List-$I$	List-$II$
$a$. $(i)$ $NaOH$,$(ii)$ $CO_2$,$(iii)$ $H^{+}$	$i$. Benzoquinone
$b$. $(i)$ Aqueous $NaOH + CHCl_3$,$(ii)$ $H^{+}$	$ii$. Benzene
$c$. $Zn$ dust,$\Delta$	$iii$. Salicylaldehyde
$d$. $Na_2Cr_2O_7, H_2SO_4$	$iv$. Salicylic acid

Choose the correct answer from the options given below:

$C_6H_6 + CH_3-CH=CH_2$ $\xrightarrow{H_3PO_4} A$ $\xrightarrow{O_2, \text{heat}} B$ $\xrightarrow{\text{dil. } H_2SO_4} C + D$. $A, C$ and $D$ are:

In which of the following,ortho/para substitution by an electrophile is very facile?